:doc:`ServiceResource <index>` / Sub-Resource / BucketLogging

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BucketLogging
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.. py:method:: S3.ServiceResource.BucketLogging(bucket_name)

  Creates a BucketLogging resource.::

    bucket_logging = s3.BucketLogging('bucket_name')

  :type bucket_name: string
  :param bucket_name: The BucketLogging's bucket_name identifier. This **must** be set.
  
  :rtype: :py:class:`S3.BucketLogging`
  :returns: A BucketLogging resource
  