:doc:`ServiceResource <index>` / Sub-Resource / Bucket

******
Bucket
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.. py:method:: S3.ServiceResource.Bucket(name)

  Creates a Bucket resource.::

    bucket = s3.Bucket('name')

  :type name: string
  :param name: The Bucket's name identifier. This **must** be set.
  
  :rtype: :py:class:`S3.Bucket`
  :returns: A Bucket resource
  